Version 1 (modified by simonmar@…, 8 years ago) (diff) |
---|

# Proposal: make the $ operator left-associative

## Arguments in favour

0) $ was introduced as a combinator for function application. Therefore we might expect that whenever we have a function application we can stick a $ in there. But this is not the case. Consider the following expression:

f x y

There are two applications here and if $ behaved like function application we would be able to write:

f $ x $ y

But as it is now this expression means something completely different.

(these following points taken from Dan Doel's post on the haskell-prime mailing list)

1) Anything of the form:

f $ g $ h $ x

with right associative ($) can instead be written:

f . g . h $ x

where the associativity of ($) doesn't matter. It's not uncommon to want to peel off the end of such a pipeline to eliminate a point. For the second form, such a translation is:

\x -> f . g . h $ x ==> f . g . h

However:

\x -> f $ g $ h $ x ==> f $ g $ h

Is invalid, so one might argue that writing such pipelines with composition is a better habit to get into, as it allows easier cleanup of code in this way (if you like somewhat point-free code, that is).

2) Left associative ($) allows you to eliminate more parentheses. Per #1, any parentheses eliminated by right associative ($) can be eliminated by (.) and a single ($). However, left associative ($) allows, for instance:

f (g x) (h y) ==> f $ g x $ h y

3) Left associative ($) is consistent with left associative ($!). The right associative version of the latter is inconvenient, because it only allows things to be (easily) strictly applied to the last argument of a function. Needing to strictly apply to other arguments gives rise to things like:

(f $! x) y z ((f $! x) $! y) $! z

Left associative, these are:

f $! x $ y $ z f $! x $! y $! z

There may be more arguments, but those are the ones I've heard that I can think of at the moment. #3 strikes me as the most likely to bite people (the other two are more stylistic issues), but I suppose I don't know the relative frequency of strict pipelines (f $! g $! x) versus strict applications at non-final arguments.

## Arguments against

- This would break a
*lot*of code.